In the circuit below, if a dielectric is inserted into C2 then the charge on C1 will

Question

In the circuit below, if a dielectric is inserted into C2 then the charge on C1 will (A) Increase (B) Decrease (C) Remain same (D) Be halved

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/66657f88503ee268753576b2d2fbbc8a-.png" /> q1=(C1 C2 V/C1+C2) q1'=(K C1 C2 V/C1+K C2) q1 ' > q1, so charge increases.

Q. In the circuit below, if a dielectric is inserted into $C_{2}$ then the charge on $C_{1}$ will

Increase

Decrease

Remain same

Be halved

$q_{1} = \frac{C _{1} C _{2} V}{C _{1} + C _{2}}$
$q_{1}^{'} = \frac{K C _{1} C _{2} V}{C _{1} + K C _{2}}$
$q_{1}^{'} > q_{1}$ , so charge increases.

Q. In the circuit below, if a dielectric is inserted into C2​ then the charge on C1​ will