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  4. In the circuit below, if a dielectric is inserted into C2 then the charge on C1 will

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Q. In the circuit below, if a dielectric is inserted into $C_{2}$ then the charge on $C_{1}$ willPhysics Question Image

Electrostatic Potential and Capacitance

Solution:

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$q_{1}=\frac{C_{1} C_{2} V}{C_{1}+C_{2}} $
$q_{1}'=\frac{K C_{1} C_{2} V}{C_{1}+K C_{2}}$
$q_{1} ' > q_{1}$, so charge increases.