In the arrangement shown, by what acceleration the boy must go up so that 100 kg block remains stationary on the wedge. The wedge is fixed and friction is absent everywhere. (Take g=10 m s- 2 )

Question

In the arrangement shown, by what acceleration the boy must go up so that 100 kg block remains stationary on the wedge. The wedge is fixed and friction is absent everywhere. (Take g=10 m s- 2 ) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-sdxyddrfhatm.png" /> (A) 2ms- 2 (B) 4ms- 2 (C) 8ms- 2 (D) 6ms- 2

Tardigrade Admin · Accepted Answer

For block to be stationary T=800N If man moves up by acceleration a Solution

T-mg=ma 800-500=50a , a=6ms- 2

Q. In the arrangement shown, by what acceleration the boy must go up so that $100 k g$ block remains stationary on the wedge. The wedge is fixed and friction is absent everywhere. (Take $g = 10 m s^{- 2}$ )

$2 m s^{- 2}$

$4 m s^{- 2}$

$8 m s^{- 2}$

$6 m s^{- 2}$

For block to be stationary $T = 800 N$
If man moves up by acceleration $a$

$T - m g = ma$
$800 - 500 = 50 a$ ,
$a = 6 m s^{- 2}$

Q. In the arrangement shown, by what acceleration the boy must go up so that 100kg block remains stationary on the wedge. The wedge is fixed and friction is absent everywhere. (Take g=10ms−2 )

2ms−2

4ms−2

8ms−2

6ms−2