Question

In the arrangement shown, by what acceleration the boy must go up so that $100 \, kg$ block remains stationary on the wedge. The wedge is fixed and friction is absent everywhere. (Take $g=10 \, m \, s^{- 2}$ )

• A. $2ms^{- 2}$
• B. $4ms^{- 2}$
• C. $8ms^{- 2}$
• D. $6ms^{- 2}$

Answer 1

Answer: (D)

For block to be stationary $T=800N$
If man moves up by acceleration $a$

$T-mg=ma$
$800-500=50a$ ,
$a=6ms^{- 2}$