In the adjacent circuit, the instantaneous current equation is

Question

In the adjacent circuit, the instantaneous current equation is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-i1ptzog9md2zzgez.jpg" /> (A) 2sin (100 t - (π /4)) (B) √2sin (100 t - (π /4)) (C) √2sin (200 t - (π /4)) (D) √2(100 t + (π /4))

Tardigrade Admin · Accepted Answer

Let φ is the phase difference between V and i texttan φ=(XL/R)=(ω L/R)=(100 × 1/100)=1 ⇒ φ=(π /4) Since this is an LR circuit, V will lead i ∴ The instantaneous current equation will be i=i0 textsin (100 t - φ) where φ=(π /4) and i0=(V0/Z) i0=(V0/√R2 + (ω L)2)=(200/√(100)2 + (100 × 1)2)=√2 ∴ i=√2 textsin (100 t - (π /4))

Q. In the adjacent circuit, the instantaneous current equation is

$2 s in (100 t - \frac{π}{4})$

$2 s in (100 t - \frac{π}{4})$

$2 s in (200 t - \frac{π}{4})$

$2 (100 t + \frac{π}{4})$

Q. In the adjacent circuit, the instantaneous current equation is

2sin(100t−4π​)

2​sin(100t−4π​)

2​sin(200t−4π​)

2​(100t+4π​)

$2 s in (100 t - \frac{π}{4})$

$2 s in (100 t - \frac{π}{4})$

$2 s in (200 t - \frac{π}{4})$

$2 (100 t + \frac{π}{4})$