In the absence of magnetic and electric fields, considering a multi-electron atom, which of the following are degenerate orbitals? (.a.)n=1,l=0,m=0 (b)n=2,l=0,m=0 (c)n=2,l=1,m=1 (d)n=3,l=2,m=1 (e)n=3,l=2,m=0

Question

In the absence of magnetic and electric fields, considering a multi-electron atom, which of the following are degenerate orbitals? (.a.)n=1,l=0,m=0 (b)n=2,l=0,m=0 (c)n=2,l=1,m=1 (d)n=3,l=2,m=1 (e)n=3,l=2,m=0 (A) (.d.) and (.e.) (B) (.c.) and (.d.) (C) (.b.) and (.c.) (D) (.a.) and (.b.)

Tardigrade Admin · Accepted Answer

(.a.)1s(.b.)2s(.c.)2p(.d.)3d(.e.)3d In the absence of any field, 3d in (.d.) and (.e.) will be of equal energy.

Q. In the absence of magnetic and electric fields, considering a multi-electron atom, which of the following are degenerate orbitals?
$(a) n = 1, l = 0, m = 0$
$(b) n = 2, l = 0, m = 0$
$(c) n = 2, l = 1, m = 1$
$(d) n = 3, l = 2, m = 1$
$(e) n = 3, l = 2, m = 0$

$(d)$ and $(e)$

$(c)$ and $(d)$

$(b)$ and $(c)$

$(a)$ and $(b)$

$(a) 1 s (b) 2 s (c) 2 p (d) 3 d (e) 3 d$
In the absence of any field, $3 d$ in $(d)$ and $(e)$ will be of equal energy.

Q. In the absence of magnetic and electric fields, considering a multi-electron atom, which of the following are degenerate orbitals? (a)n=1,l=0,m=0 (b)n=2,l=0,m=0 (c)n=2,l=1,m=1 (d)n=3,l=2,m=1 (e)n=3,l=2,m=0

(d) and (e)

(c) and (d)

(b) and (c)

(a) and (b)