Question

In the absence of magnetic and electric fields, considering a multi-electron atom, which of the following are degenerate orbitals?
$\left(\right.a\left.\right)n=1,l=0,m=0$
$\left(b\right)n=2,l=0,m=0$
$\left(c\right)n=2,l=1,m=1$
$\left(d\right)n=3,l=2,m=1$
$\left(e\right)n=3,l=2,m=0$

• A. $\left(\right.d\left.\right)$ and $\left(\right.e\left.\right)$
• B. $\left(\right.c\left.\right)$ and $\left(\right.d\left.\right)$
• C. $\left(\right.b\left.\right)$ and $\left(\right.c\left.\right)$
• D. $\left(\right.a\left.\right)$ and $\left(\right.b\left.\right)$

Answer 1

Answer: (A)

$\left(\right.a\left.\right)1s\left(\right.b\left.\right)2s\left(\right.c\left.\right)2p\left(\right.d\left.\right)3d\left(\right.e\left.\right)3d$
In the absence of any field, $3d$ in $\left(\right.d\left.\right)$ and $\left(\right.e\left.\right)$ will be of equal energy.