Question

In sine wave, minimum distance between $2$ particles always having same speed is

• A. $\frac{\lambda }{2}$
• B. $\frac{\lambda }{4}$
• C. $\frac{\lambda }{3}$
• D. $\lambda$

Answer 1

Answer: (A)

Sine wave

Particle velocity $v_p=\frac{dy}{dt}=$ slope of wave at that point.
As slope at $A$ and $B$ is zero. Hence the velocity at $A$ and $B$ will be same. Distance between $A$ and $B$ is $\frac{\lambda }{2}$.