Question

In sine wave, minimum distance between $ 2 $ particles always having same speed is

• A. $ \frac{\lambda}{2} $
• B. $ \frac{\lambda}{4} $
• C. $ \frac{\lambda}{3} $
• D. $ \lambda $

Answer 1

Answer: (A)

Sine wave

Particle velocity $v_{p}=\frac{d y}{d t}=$ slope of wave at that point.
As slope at $A$ and $B$ is zero. Hence the velocity at $A$ and $B$ will be same. Distance between $A$ and $B$ is $\frac{\lambda}{2}$.