Question

In SHM, the acceleration is ahead of velocity by a phase angle

• A. $0^{\circ }$
• B. $\frac{\pi }{2}$
• C. $\pi$
• D. $2\pi$

Answer 1

Answer: (B)

in SHM, the acceleration is ahead of velocity by a phase angle $\frac{\pi }{2}$
$v=A\omega sin(\omega t+\frac{\pi }{2})$
$a=A{\omega }^{2}sin(\omega t+\pi )$