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Q. In SHM, the acceleration is ahead of velocity by a phase angle

Odisha JEEOdisha JEE 2010Oscillations

Solution:

in SHM, the acceleration is ahead of velocity by a phase angle $\frac{\pi}{2}$
$ \, \, \, \, \, \, \, \, \, \, \, v=A \omega sin\bigg(\omega t +\frac{\pi}{2}\bigg)$
$ \, \, \, \, \, \, \, \, \, \, \, a=A\omega^2 sin (\omega t +\pi)$