In resonance tube two successive positions of resonance are obtained at 15 cm and 48 cm. If the frequency of the fork is 500 cps, the velocity of sound is

Question

In resonance tube two successive positions of resonance are obtained at 15 cm and 48 cm. If the frequency of the fork is 500 cps, the velocity of sound is (A) 330 m/s (B) 300 m/s (C) 1000 m/s (D) 360 m/s

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/06d8c8f459aae9ddb6c3e50c9b67479c-.png" /> l1+e=(λ/4) l2+e=(3 λ/4) l2-l1=(λ/2) 0.48-0.15=(λ/2) 0 λ=0.66 Velocity =f λ=500 × 0.66=330 m / s

Q. In resonance tube two successive positions of resonance are obtained at $15 c m$ and $48 c m$ . If the frequency of the fork is $500 c p s$ , the velocity of sound is

330 m/s

300 m/s

1000 m/s

360 m/s

$l_{1} + e = \frac{λ}{4}$
$l_{2} + e = \frac{3 λ}{4}$
$l_{2} - l_{1} = \frac{λ}{2}$
$0.48 - 0.15 = \frac{λ}{2}$
$0 λ = 0.66$
Velocity $= f λ = 500 \times 0.66 = 330 m / s$

Q. In resonance tube two successive positions of resonance are obtained at 15cm and 48cm. If the frequency of the fork is 500cps, the velocity of sound is