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  4. In resonance tube two successive positions of resonance are obtained at 15 cm and 48 cm. If the frequency of the fork is 500 cps, the velocity of sound is

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Q. In resonance tube two successive positions of resonance are obtained at $15\, cm$ and $48 \,cm$. If the frequency of the fork is $500 \,cps$, the velocity of sound is

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Solution:

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$l_{1}+e=\frac{\lambda}{4}$
$l_{2}+e=\frac{3 \lambda}{4}$
$l_{2}-l_{1}=\frac{\lambda}{2}$
$0.48-0.15=\frac{\lambda}{2}$
$0 \lambda=0.66$
Velocity $=f \lambda=500 \times 0.66=330\, m / s$