In Ramsden eyepiece the focal length of each lens is F. The distance of the image formed by the objective lens from the eye lens is

Question

In Ramsden eyepiece the focal length of each lens is F. The distance of the image formed by the objective lens from the eye lens is (A)  (14 F/15)  (B)  (13 F/14)  (C)  (12 F/13)  (D)  (11 F/12)

Tardigrade Admin · Accepted Answer

The distance of image formed by the objective lens from the eye lens =(2F/3)+(F/4) =(8F+3F/12)=(11F/12)

Q. In Ramsden eyepiece the focal length of each lens is F. The distance of the image formed by the objective lens from the eye lens is

$\frac{14 F}{15}$

$\frac{13 F}{14}$

$\frac{12 F}{13}$

$\frac{11 F}{12}$

The distance of image formed by the objective lens from the eye lens $= \frac{2 F}{3} + \frac{F}{4}$ $= \frac{8 F + 3 F}{12} = \frac{11 F}{12}$

Q. In Ramsden eyepiece the focal length of each lens is F. The distance of the image formed by the objective lens from the eye lens is

1514F​

1413F​

1312F​

1211F​

The distance of image formed by the objective lens from the eye lens =32F​+4F​ =128F+3F​=1211F​

$\frac{14 F}{15}$

$\frac{13 F}{14}$

$\frac{12 F}{13}$

$\frac{11 F}{12}$

The distance of image formed by the objective lens from the eye lens $= \frac{2 F}{3} + \frac{F}{4}$ $= \frac{8 F + 3 F}{12} = \frac{11 F}{12}$