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Physics
In Ramsden eyepiece the focal length of each lens is F. The distance of the image formed by the objective lens from the eye lens is
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Q. In Ramsden eyepiece the focal length of each lens is F. The distance of the image formed by the objective lens from the eye lens is
EAMCET
EAMCET 2007
A
$ \frac{14\,F}{15} $
B
$ \frac{13\,F}{14} $
C
$ \frac{12\,F}{13} $
D
$ \frac{11\,F}{12} $
Solution:
The distance of image formed by the objective lens from the eye lens $ =\frac{2F}{3}+\frac{F}{4} $ $ =\frac{8F+3F}{12}=\frac{11F}{12} $