In ψ321, the sum of angular momentum, spherical nodes and angular node is

Question

In ψ321, the sum of angular momentum, spherical nodes and angular node is (A) (√6 h + 4 π /2 π ) (B) (√6 h/2 π )+3 (C) (√6 h + 2 π /2 π ) (D) (√6 h + 8 π /2 π )

Tardigrade Admin · Accepted Answer

ψ321:n=3,l=2,m=1 Angular momentum =(h/2 π )√l (. l + 1 .)=(√6 h/2 π ) Spherical nodes =3-2-1=0; Angular node =2 Sum of all the above =(√6 h/2 π )+2=(√6 h + 4 π /2 π )

Q. In $ψ_{321},$ the sum of angular momentum, spherical nodes and angular node is

$\frac{6 h + 4 π}{2 π}$

$\frac{6 h}{2 π} + 3$

$\frac{6 h + 2 π}{2 π}$

$\frac{6 h + 8 π}{2 π}$

$ψ_{321} : n = 3, l = 2, m = 1$
Angular momentum $= \frac{h}{2 π} l (l + 1) = \frac{6 h}{2 π}$
Spherical nodes $= 3 - 2 - 1 = 0;$ Angular node $= 2$
Sum of all the above $= \frac{6 h}{2 π} + 2 = \frac{6 h + 4 π}{2 π}$

Q. In ψ321​, the sum of angular momentum, spherical nodes and angular node is

2π6​h+4π​

2π6​h​+3

2π6​h+2π​

2π6​h+8π​