Question

In $\psi_{321},$ the sum of angular momentum, spherical nodes and angular node is

• A. $\frac{\sqrt{6} h + 4 \pi }{2 \pi }$
• B. $\frac{\sqrt{6} h}{2 \pi }+3$
• C. $\frac{\sqrt{6} h + 2 \pi }{2 \pi }$
• D. $\frac{\sqrt{6} h + 8 \pi }{2 \pi }$

Answer 1

Answer: (A)

$\psi_{321}:n=3,l=2,m=1$
Angular momentum $=\frac{h}{2 \pi }\sqrt{l \left(\right. l + 1 \left.\right)}=\frac{\sqrt{6} h}{2 \pi }$
Spherical nodes $=3-2-1=0;$ Angular node $=2$
Sum of all the above $=\frac{\sqrt{6} h}{2 \pi }+2=\frac{\sqrt{6} h + 4 \pi }{2 \pi }$