In potentiometer experiment, a cell is balanced at 52 cm. If it is shunted by 5 Ω, now balaned at 40 cm. Its internal resistance :-

Question

In potentiometer experiment, a cell is balanced at 52 cm. If it is shunted by 5 Ω, now balaned at 40 cm. Its internal resistance :- (A) 5 Ω (B) 3 Ω (C) 1.5 Ω (D) 1 Ω

Tardigrade Admin · Accepted Answer

r =((ℓ1-ℓ2/ℓ2)) R =((52-40/ℓ2)) × 5=1.5 Ω

Q. In potentiometer experiment, a cell is balanced at $52 c m$ . If it is shunted by $5 Ω$ , now balaned at $40 c m$ . Its internal resistance :-

$5 Ω$

$3 Ω$

$1.5 Ω$

$1 Ω$

$r = (\frac{ℓ _{1} - ℓ _{2}}{ℓ _{2}}) R$
$= (\frac{52 - 40}{ℓ _{2}}) \times 5 = 1.5 Ω$

Q. In potentiometer experiment, a cell is balanced at 52cm. If it is shunted by 5Ω, now balaned at 40cm. Its internal resistance :-

5Ω

3Ω

1.5Ω

1Ω