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Physics
In potentiometer experiment, a cell is balanced at 52 cm. If it is shunted by 5 Ω, now balaned at 40 cm. Its internal resistance :-
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Q. In potentiometer experiment, a cell is balanced at $52\, cm$. If it is shunted by $5\, \Omega$, now balaned at $40\, cm$. Its internal resistance :-
Current Electricity
A
$5\, \Omega$
B
$3\, \Omega$
C
$1.5\, \Omega$
D
$1\, \Omega$
Solution:
$r =\left(\frac{\ell_{1}-\ell_{2}}{\ell_{2}}\right) R$
$=\left(\frac{52-40}{\ell_{2}}\right) \times 5=1.5\, \Omega$