In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is M. (Round off to the Nearest Integer). [Given: pKa (acetic acid) =4.74]

Question

In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is M. (Round off to the Nearest Integer). [Given: pKa (acetic acid) =4.74] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

pH = pKa + log ([ CB ]/[ WA ]) 5.74=4.74+ log ([CB ]/1) ⇒ [ CB ]=10 M

Q. In order to prepare a buffer solution of $p H 5.74$ , sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is $1.0 M$ , the concentration of sodium acetate in the buffer is______ M. (Round off to the Nearest Integer).
[Given : pKa (acetic acid) $= 4.74]$

$p H = p K a + lo g \frac{[ CB ]}{[ W A ]}$

$5.74 = 4.74 + lo g \frac{[ CB ]}{1}$

$\Rightarrow [CB] = 10 M$

Q. In order to prepare a buffer solution of pH5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0M, the concentration of sodium acetate in the buffer is______ M. (Round off to the Nearest Integer). [Given : pKa (acetic acid) =4.74]

pH=pKa+log[WA][CB]​ 5.74=4.74+log1[CB]​ ⇒[CB]=10M

Q. In order to prepare a buffer solution of $p H 5.74$ , sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is $1.0 M$ , the concentration of sodium acetate in the buffer is______ M. (Round off to the Nearest Integer).
[Given : pKa (acetic acid) $= 4.74]$

$p H = p K a + lo g \frac{[ CB ]}{[ W A ]}$

$5.74 = 4.74 + lo g \frac{[ CB ]}{1}$

$\Rightarrow [CB] = 10 M$