In order to measure the period of a simple pendulum using a stop clock, a student repeated the experiment for 10 times and noted down the time period for each experiment as 5.1, 5.0, 4.9, 5.1, 5.0, 4.9, 5.1, 5.0, 4.9 s . The correct way of expressing the result for the period is

Question

In order to measure the period of a simple pendulum using a stop clock, a student repeated the experiment for 10 times and noted down the time period for each experiment as 5.1, 5.0, 4.9, 5.1, 5.0, 4.9, 5.1, 5.0, 4.9 s . The correct way of expressing the result for the period is (A) 4.99 s (B) 5.0 s (C) 5.00 s (D) 4.9 s

Tardigrade Admin · Accepted Answer

Mean =(∑ xi fi/10)=((4.9 × 4) + (5.0 × 3) + (5.1 × 3)/10)=4.99 s Which can be round off to 5.0 s correct to two significant figures.

Q. In order to measure the period of a simple pendulum using a stop clock, a student repeated the experiment for $10$ times and noted down the time period for each experiment as $5.1, 5.0, 4.9, 5.1, 5.0, 4.9, 5.1, 5.0, 4.9 s$ . The correct way of expressing the result for the period is

$4.99 s$

$5.0 s$

$5.00 s$

$4.9 s$

Mean $= \frac{\sum x _{i} f _{i}}{10} = \frac{( 4.9 \times 4 ) + ( 5.0 \times 3 ) + ( 5.1 \times 3 )}{10} = 4.99 s$
Which can be round off to $5.0 s$ correct to two significant figures.

Q. In order to measure the period of a simple pendulum using a stop clock, a student repeated the experiment for 10 times and noted down the time period for each experiment as 5.1,5.0,4.9,5.1,5.0,4.9,5.1,5.0,4.9s . The correct way of expressing the result for the period is

4.99s

5.0s

5.00s

4.9s