1. Tardigrade
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  4. In order to measure the period of a simple pendulum using a stop clock, a student repeated the experiment for 10 times and noted down the time period for each experiment as 5.1, 5.0, 4.9, 5.1, 5.0, 4.9, 5.1, 5.0, 4.9 s . The correct way of expressing the result for the period is

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Q. In order to measure the period of a simple pendulum using a stop clock, a student repeated the experiment for $10$ times and noted down the time period for each experiment as $5.1, \, 5.0, \, 4.9, \, 5.1, \, 5.0, \, 4.9, \, 5.1, \, 5.0, \, 4.9 \, s$ . The correct way of expressing the result for the period is

NTA AbhyasNTA Abhyas 2022

Solution:

Mean $=\frac{\sum x_{i} f_{i}}{10}=\frac{\left(4.9 \times 4\right) + \left(5.0 \times 3\right) + \left(5.1 \times 3\right)}{10}=4.99 \, s$
Which can be round off to $5.0 \, s$ correct to two significant figures.