In ICl 4 ominus, shape is square planar. The number of bond pair - lone pair repulsion at 90° are:-

Question

In ICl 4 ominus, shape is square planar. The number of bond pair - lone pair repulsion at 90° are:- (A) 6 (B) 4 (C) 12 (D) 8

Tardigrade Admin · Accepted Answer

ICl 4-has square planar shape with sp 3 d 2 hybridisation. There are 4 bond pairs and 2 lone pairs. Each lone pair is at a right angle to bond pairs. So, total is 2 × 4=8 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/c50770e1dcd1b0c7cb2c72f5bd54843c-.png" />

Q. In $I C l_{4}^{⊖}$ , shape is square planar. The number of bond pair - lone pair repulsion at $9 0^{\circ}$ are:-

6

4

12

8

$I C l_{4}^{-}$ has square planar shape with $s p^{3} d^{2}$ hybridisation. There are 4 bond pairs and 2 lone pairs.
Each lone pair is at a right angle to bond pairs.
So, total is $2 \times 4 = 8$

Q. In ICl4⊖​, shape is square planar. The number of bond pair - lone pair repulsion at 90∘ are:-

6

4

12

8

ICl4−​has square planar shape with sp3d2 hybridisation. There are 4 bond pairs and 2 lone pairs. Each lone pair is at a right angle to bond pairs. So, total is 2×4=8

Q. In $I C l_{4}^{⊖}$ , shape is square planar. The number of bond pair - lone pair repulsion at $9 0^{\circ}$ are:-

$I C l_{4}^{-}$ has square planar shape with $s p^{3} d^{2}$ hybridisation. There are 4 bond pairs and 2 lone pairs.
Each lone pair is at a right angle to bond pairs.
So, total is $2 \times 4 = 8$