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Q.
In $ICl _{4}^{\ominus}$, shape is square planar. The number of bond pair - lone pair repulsion at $90^{\circ}$ are:-
Chemical Bonding and Molecular Structure
Solution:
$ICl _{4}^{-}$has square planar shape with $sp ^{3} d ^{2}$ hybridisation. There are 4 bond pairs and 2 lone pairs.
Each lone pair is at a right angle to bond pairs.
So, total is $2 \times 4=8$