In HS- , I- , R -NH2, NH3 order of proton accepting tendency will be

Question

In HS- , I- , R -NH2, NH3 order of proton accepting tendency will be (A) I- >NH3 >RNH2 >HS- (B) NH3 > RNH2 > HS- > I- (C) RNH2 > NH3 > HS- > I- (D) HS- > RNH2 > NH3 > I-

Tardigrade Admin · Accepted Answer

Basic strength << rate of accepting a proton.
In

R_{- N H_{2}}^{∙∙}, N -

has lone pair of electron which intensity due to electrons releasing R-group and increase the tendency to donate lone pair of electrons to H+. Secondly as the size of the ion increases, there is less attraction for H+ and form weaker bond with H-atom and less basic. The order of the given series is

RN H_{2} > N H_{3} > H S^{-} > I^{-}

Q. In $H S^{-}, I^{-}, R - N H_{2}, N H_{3}$ order of proton accepting tendency will be

$I^{-} > N H_{3} > RN H_{2} > H S^{-}$

$N H_{3} > RN H_{2} > H S^{-} > I^{-}$

$RN H_{2} > N H_{3} > H S^{-} > I^{-}$

$H S^{-} > RN H_{2} > N H_{3} > I^{-}$

Q. In HS−,I−,R−NH2​,NH3​ order of proton accepting tendency will be

I−>NH3​>RNH2​>HS−

NH3​>RNH2​>HS−>I−

RNH2​>NH3​>HS−>I−

HS−>RNH2​>NH3​>I−

Q. In $H S^{-}, I^{-}, R - N H_{2}, N H_{3}$ order of proton accepting tendency will be

$I^{-} > N H_{3} > RN H_{2} > H S^{-}$

$N H_{3} > RN H_{2} > H S^{-} > I^{-}$

$RN H_{2} > N H_{3} > H S^{-} > I^{-}$

$H S^{-} > RN H_{2} > N H_{3} > I^{-}$