Thank you for reporting, we will resolve it shortly
Q.
In $HS^- , I^- , R -NH_2, NH_3$ order of proton accepting tendency will be
AIPMTAIPMT 2001Equilibrium
Solution:
Basic strength << rate of accepting a proton.
In $R_{-NH_2}^{\bullet \bullet}, N-$has lone pair of electron which intensity due to electrons releasing R-group and increase the tendency to donate lone pair of electrons to H+. Secondly as the size of the ion increases, there is less attraction for H+ and form weaker bond with H-atom and less basic. The order of the given series is
$ \, \, \, \, \, \, \, \, \, \, \, \, \, \, \, RNH_2 > NH_3 > HS^- > I^-$