In fluorite structure (CaF2)

Question

In fluorite structure (CaF2) (A) Ca++ ions are ccp and F- ions are present in all the tetrahedral voids (B) Ca++ ions are ccp and F- ions are present in all the octahedral voids (C) Ca++ ions are ccp and F- ions are present in all the octahedral voids and half of ions are (D) None of the above

Tardigrade Admin · Accepted Answer

Ca2+ ions are ccp and F- ions are present in the tetrahedral voids. So, the no. of Ca2+ ions is 4 and no. of F- ions is 8. So, the formula of the calcium fluoride is Ca4F8 or, the simplest formula of calcium fluoride is CaF2

Q. In fluorite structure $(C a F_{2})$

$C a^{++}$ ions are ccp and $F^{-}$ ions are present in all the tetrahedral voids

$C a^{++}$ ions are ccp and $F^{-}$ ions are present in all the octahedral voids

$C a^{++}$ ions are ccp and $F^{-}$ ions are present in all the octahedral voids and half of ions are

None of the above

$C a^{2 +}$ ions are ccp and $F^{-}$ ions are present in the tetrahedral voids. So, the no. of $C a^{2 +}$ ions is $4$ and no. of $F^{-}$ ions is $8$ .
So, the formula of the calcium fluoride is $C a_{4} F_{8}$ or, the simplest formula of calcium fluoride is $C a F_{2}$

Q. In fluorite structure (CaF2​)

Ca++ ions are ccp and F− ions are present in all the tetrahedral voids

Ca++ ions are ccp and F− ions are present in all the octahedral voids

Ca++ ions are ccp and F− ions are present in all the octahedral voids and half of ions are