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  4. In fluorite structure (CaF2)

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Q. In fluorite structure $(CaF_2)$

The Solid State

Solution:

$Ca^{2+}$ ions are ccp and $F^-$ ions are present in the tetrahedral voids. So, the no. of $Ca^{2+}$ ions is $4$ and no. of $F^-$ ions is $8$.
So, the formula of the calcium fluoride is $Ca_4F_8$ or, the simplest formula of calcium fluoride is $CaF_2$