In equimolar solution of glucose, NaCl and BaCl 2, the order of osmotic pressure is as follow

Question

In equimolar solution of glucose, NaCl and BaCl 2, the order of osmotic pressure is as follow (A) Glucose > NaCl > BaCl 2 (B) BaCl 2> NaCl > Glucose (C) NaCl > BaCl 2> Glucose (D) Glucose > BaCl 2> NaCl

Tardigrade Admin · Accepted Answer

BaCl 2 ⇒ Ba 2++2 Cl -=3 ion NaCl ⇒ Na ++ Cl -=2 ion Glucose ⇒ No ionization ∴ BaCl 2> NaCl > Glucose

Q. In equimolar solution of glucose, $N a Cl$ and $B a C l_{2}$ , the order of osmotic pressure is as follow

Glucose $> N a Cl > B a C l_{2}$

$B a C l_{2} > N a Cl >$ Glucose

$N a Cl > B a C l_{2} >$ Glucose

Glucose $> B a C l_{2} > N a Cl$

$B a C l_{2} \Rightarrow B a^{2 +} + 2 C l^{-} = 3 i o n$

$N a Cl \Rightarrow N a^{+} + C l^{-} = 2 i o n$

Glucose $\Rightarrow$ No ionization

$∴ B a C l_{2} > N a Cl >$ Glucose

Q. In equimolar solution of glucose, NaCl and BaCl2​, the order of osmotic pressure is as follow

Glucose >NaCl>BaCl2​

BaCl2​>NaCl> Glucose

NaCl>BaCl2​> Glucose

Glucose >BaCl2​>NaCl