Question

In equimolar solution of glucose, $NaCl$ and $BaCl _{2}$, the order of osmotic pressure is as follow

• A. Glucose $> NaCl > BaCl _{2}$
• B. $BaCl _{2}> NaCl >$ Glucose
• C. $NaCl > BaCl _{2}>$ Glucose
• D. Glucose $> BaCl _{2}> NaCl$

Answer 1

Answer: (B)

$BaCl _{2} \Rightarrow Ba ^{2+}+2 Cl ^{-}=3\, ion$

$ NaCl \Rightarrow Na ^{+}+ Cl ^{-}=2 \,ion$

Glucose $\Rightarrow $ No ionization

$\therefore BaCl _{2}> NaCl >$ Glucose