Question

In case of dimensions of electric field and electric dipole moment the power of mass is respectively,

• A. $1$, $1$
• B. $1$, $0$
• C. $0$, $1$
• D. $0$, $0$

Answer 1

Answer: (B)

Electric field, $E=\frac{F}{q}$
Where, $F=$ force and $q=$ electric charge
Dimensions of E or [E] $=\frac{\left[ML{T}^{-2}\right]}{[AT]}=\left[ML{T}^{-3}{A}^{-1}\right]$
Power of mass $=1$
Electric dipole moment, $m=1\times A$
where, $I=$ current and $A=$ area
Dimensions of $m=[M]=\left[A{L}^2\right]$
$=\left[M^0{L}^2{T}^{\circ }A\right]$
Hence, power of mass $=0$