In Carius method of estimation of halogens, 0.5 g of an organic compound gave 0.376 g of AgBr. The percentage of bromine in the compound is (Atomic mass of Ag =108 u and Br =80 u )

Question

In Carius method of estimation of halogens, 0.5 g of an organic compound gave 0.376 g of AgBr. The percentage of bromine in the compound is (Atomic mass of Ag =108 u and Br =80 u ) (A) 16 % (B) 48 % (C) 64 % (D) 32 %

Tardigrade Admin · Accepted Answer

Percentage of bromine =(80/188) × (0.376/0.5) × 100 =32 %

Q. In Carius method of estimation of halogens, $0.5 g$ of an organic compound gave $0.376 g$ of $A g B r$ . The percentage of bromine in the compound is (Atomic mass of $A g = 108 u$ and $B r = 80 u$ )

$16%$

$48%$

$64%$

$32%$

Percentage of bromine $= \frac{80}{188} \times \frac{0.376}{0.5} \times 100$
$= 32%$

Q. In Carius method of estimation of halogens, 0.5g of an organic compound gave 0.376g of AgBr. The percentage of bromine in the compound is (Atomic mass of Ag=108u and Br=80u )

16%

48%

64%

32%