In Bohr's model of the hydrogen atom, the ratio between the period of revolution of an electron in the orbit of n=1 to the period of revolution of the electron in the orbit n=2 is

Question

In Bohr's model of the hydrogen atom, the ratio between the period of revolution of an electron in the orbit of n=1 to the period of revolution of the electron in the orbit n=2 is (A) 1: 2 (B) 2: 1 (C) 1: 4 (D) 1: 8

Tardigrade Admin · Accepted Answer

Period of electron in n text th orbit Tn=(2 π rn/vn) Tn=(2 π r0 n3/v0) T1: T2=1: 8

Q. In Bohr's model of the hydrogen atom, the ratio between the period of revolution of an electron in the orbit of $n = 1$ to the period of revolution of the electron in the orbit $n = 2$ is

$1 : 2$

$2 : 1$

$1 : 4$

$1 : 8$

Period of electron in $n^{th}$ orbit
$T_{n} = \frac{2 π r _{n}}{v _{n}}$
$T_{n} = \frac{2 π r _{0} n ^{3}}{v _{0}}$
$T_{1} : T_{2} = 1 : 8$

Q. In Bohr's model of the hydrogen atom, the ratio between the period of revolution of an electron in the orbit of n=1 to the period of revolution of the electron in the orbit n=2 is

1:2

2:1

1:4

1:8