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Q. In Bohr's model of the hydrogen atom, the ratio between the period of revolution of an electron in the orbit of $n=1$ to the period of revolution of the electron in the orbit $n=2$ is

Atoms

Solution:

Period of electron in $n^{\text {th }}$ orbit
$T_{n}=\frac{2 \pi r_{n}}{v_{n}}$
$T_{n}=\frac{2 \pi r_{0} n^{3}}{v_{0}} $
$T_{1}: T_{2}=1: 8$