In beta minus decay a neutron transforms with the nucleus according to.

Question

In beta minus decay a neutron transforms with the nucleus according to. (A)  p→ n+e++v  (B)  n→ p+e-+ barv  (C)  n→ p+e++ barv  (D)  n→ p+e++v

Tardigrade Admin · Accepted Answer

A beta minus particle β-is an electron. Emission of β-involves transformation of a neutron into a proton, an electron and a third particle called an antineutrino. n=p+-1 β0+ barv or n arrow p+e-+ barv

Q. In beta minus decay a neutron transforms with the nucleus according to.

$p \to n + e^{+} + v$

$n \to p + e^{-} + \overset{v}{ˉ}$

$n \to p + e^{+} + \overset{v}{ˉ}$

$n \to p + e^{+} + v$

A beta minus particle $β^{-}$ is an electron.
Emission of $β^{-}$ involves transformation of a neutron into a proton, an electron and a third particle called an antineutrino.
$n = p +_{- 1} β^{0} + \overset{v}{ˉ}$
or $n \to p + e^{-} + \overset{v}{ˉ}$

Q. In beta minus decay a neutron transforms with the nucleus according to.

p→n+e++v

n→p+e−+vˉ

n→p+e++vˉ

n→p+e++v

A beta minus particle β−is an electron. Emission of β−involves transformation of a neutron into a proton, an electron and a third particle called an antineutrino. n=p+−1​β0+vˉ or n→p+e−+vˉ

$p \to n + e^{+} + v$

$n \to p + e^{-} + \overset{v}{ˉ}$

$n \to p + e^{+} + \overset{v}{ˉ}$

$n \to p + e^{+} + v$

A beta minus particle $β^{-}$ is an electron.
Emission of $β^{-}$ involves transformation of a neutron into a proton, an electron and a third particle called an antineutrino.
$n = p +_{- 1} β^{0} + \overset{v}{ˉ}$
or $n \to p + e^{-} + \overset{v}{ˉ}$