Question

In beta minus decay a neutron transforms with the nucleus according to.

• A. $ p\to n+e^{+}+v $
• B. $ n\to p+e^{-}+\bar{v} $
• C. $ n\to p+e^{+}+\bar{v} $
• D. $ n\to p+e^{+}+v $

Answer 1

Answer: (C)

A beta minus particle $\beta^{-}$is an electron.
Emission of $\beta^{-}$involves transformation of a neutron into a proton, an electron and a third particle called an antineutrino.
$n=p+_{-1} \beta^{0}+\bar{v}$
or $n \rightarrow p+e^{-}+\bar{v}$