In aqueous alkaline solution, two electron reduction of HO-2 gives

Question

In aqueous alkaline solution, two electron reduction of HO-2 gives (A) HO- (B) H2O (C) O2 (D) O-2

Tardigrade Admin · Accepted Answer

In aqueous alkaline solution, two electron reduction of HO 2-gives overset- O H. The reaction is as follows: H 2 O 2 leftharpoons H ++ HO 2- HO 2-+ H 2 O +2 e - longrightarrow 3 overset- O H

Q. In aqueous alkaline solution, two electron reduction of $H O_{2}^{-}$ gives

$H O^{-}$

$H_{2} O$

$O_{2}$

$O_{2}^{-}$

In aqueous alkaline solution, two electron reduction of $H O_{2}^{-}$ gives $O - H$ . The reaction is as follows:
$H_{2} O_{2} ⇌ H^{+} + H O_{2}^{-}$
$H O_{2}^{-} + H_{2} O + 2 e^{-} ⟶ 3 O - H$

Q. In aqueous alkaline solution, two electron reduction of HO2−​ gives

HO−

H2​O

O2​

O2−​