In aqueous alkaline solution, two electron reduction of $HO _{2}^{-}$gives $\overset{-}{ O } H$. The reaction is as follows:
$H _{2} O _{2} \rightleftharpoons H ^{+}+ HO _{2}^{-}$
$HO _{2}^{-}+ H _{2} O +2 e ^{-} \longrightarrow 3 \overset{-}{ O } H$