In an isobaric process of a diatomic gas 140 J of heat is added to N moles of the gas to increase its temperature from T1 to T2. The amount of work done by the gas in this process is

Question

In an isobaric process of a diatomic gas 140 J of heat is added to N moles of the gas to increase its temperature from T1 to T2. The amount of work done by the gas in this process is (A) 100J (B) 40J (C) 60J (D) 120J

Tardigrade Admin · Accepted Answer

Qp = n Cp(T2-T1) 140 = n (7/2) R(T2-T1) w = nR (T2-T1) = 40 J

Q. In an isobaric process of a diatomic gas 140 J of heat is added to N moles of the gas to increase its temperature from $T_{1}$ to $T_{2}$ . The amount of work done by the gas in this process is

100J

40J

60J

120J

$Q_{p} = n C_{p} (T_{2} - T_{1})$
140 = $n \frac{7}{2} R (T_{2} - T_{1})$
$w = n R (T_{2} - T_{1})$
= 40 J

Q. In an isobaric process of a diatomic gas 140 J of heat is added to N moles of the gas to increase its temperature from T1​ to T2​. The amount of work done by the gas in this process is

100J

40J

60J

120J

Qp​=nCp​(T2​−T1​) 140 = n27​R(T2​−T1​) w=nR(T2​−T1​) = 40 J

Q. In an isobaric process of a diatomic gas 140 J of heat is added to N moles of the gas to increase its temperature from $T_{1}$ to $T_{2}$ . The amount of work done by the gas in this process is

$Q_{p} = n C_{p} (T_{2} - T_{1})$
140 = $n \frac{7}{2} R (T_{2} - T_{1})$
$w = n R (T_{2} - T_{1})$
= 40 J