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Q. In an isobaric process of a diatomic gas 140 J of heat is added to N moles of the gas to increase its temperature from $T_1$ to $T_2$. The amount of work done by the gas in this process is

Solution:

$Q_p = n C_p(T_2-T_1) $
140 = $n \frac {7}{2} R(T_2-T_1)$
$w = nR (T_2-T_1)$
= 40 J