In an Experiment to find the loss of energy with respect to time in case of swinging simple pendulum, the graph between square of amplitude and time is best represented by

Question

In an Experiment to find the loss of energy with respect to time in case of swinging simple pendulum, the graph between square of amplitude and time is best represented by (A) Option 1

(B)

(C)

(D)

Tardigrade Admin · Accepted Answer

Energy = (1/2) K A2 For a damped harmonic oscillation A = Ao e- (b t/2 m) sin (. w ' t + δ .) amplitude can be written as A = A0 e- (b t/2 m) So curve between A2 v s t will be an exponential decay Solution

Q. In an Experiment to find the loss of energy with respect to time in case of swinging simple pendulum, the graph between square of amplitude and time is best represented by

Energy $= \frac{1}{2} K A^{2}$
For a damped harmonic oscillation
$A = A_{o} e^{- \frac{b t}{2 m}} s in (w^{'} t + δ)$
amplitude can be written as $A = A_{0} e^{- \frac{b t}{2 m}}$
So curve between $A^{2} v s t$
will be an exponential decay

Q. In an Experiment to find the loss of energy with respect to time in case of swinging simple pendulum, the graph between square of amplitude and time is best represented by

Energy =21​KA2 For a damped harmonic oscillation A=Ao​e−2mbt​sin(w′t+δ) amplitude can be written as A=A0​e−2mbt​ So curve between A2vst will be an exponential decay

Energy $= \frac{1}{2} K A^{2}$
For a damped harmonic oscillation
$A = A_{o} e^{- \frac{b t}{2 m}} s in (w^{'} t + δ)$
amplitude can be written as $A = A_{0} e^{- \frac{b t}{2 m}}$
So curve between $A^{2} v s t$
will be an exponential decay