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Q. In an Experiment to find the loss of energy with respect to time in case of swinging simple pendulum, the graph between square of amplitude and time is best represented by

NTA AbhyasNTA Abhyas 2020Oscillations

Solution:

Energy $= \frac{1}{2} K A^{2}$
For a damped harmonic oscillation
$A = A_{o} e^{- \frac{b t}{2 m}} sin \left(\right. w ' t + \delta \left.\right)$
amplitude can be written as $A = A_{0} e^{- \frac{b t}{2 m}}$
So curve between $A^{2} \, v s \, t$
will be an exponential decay
Solution
Solution