In an experiment on photoelectric effect, stopping potential is 1.0 V when light of wavelength 6520 mathringA is incident on the emitting surface. The stopping potential is 2.9 V for light of wavelength 3260 mathringA. The work function of the metal is

Question

In an experiment on photoelectric effect, stopping potential is 1.0 V when light of wavelength 6520 mathringA is incident on the emitting surface. The stopping potential is 2.9 V for light of wavelength 3260 mathringA. The work function of the metal is (A) 0.9 eV (B) 1.9 eV (C) 5.8 eV (D) cannot be deduced from the given data.

Tardigrade Admin · Accepted Answer

(h c/λ)=W+e Vs (h c/652 nm )=W+1 eV Also, (h c/326 nm )=W+2.9 eV Equating h c from both the equations 652(W+1)=326(W+2.9) 2(W+1)=W+2.9 W=2.9-2 W=0.9 eV

Q. In an experiment on photoelectric effect, stopping potential is $1.0 V$ when light of wavelength $6520 \overset{˚}{A}$ is incident on the emitting surface. The stopping potential is $2.9 V$ for light of wavelength $3260 \overset{˚}{A}$ . The work function of the metal is

$0.9 e V$

$1.9 e V$

$5.8 e V$

cannot be deduced from the given data.

$\frac{h c}{λ} = W + e V_{s}$
$\frac{h c}{652 nm} = W + 1 e V$
Also, $\frac{h c}{326 nm} = W + 2.9 e V$
Equating $h c$ from both the equations
$652 (W + 1) = 326 (W + 2.9)$
$2 (W + 1) = W + 2.9$
$W = 2.9 - 2$
$W = 0.9 e V$

Q. In an experiment on photoelectric effect, stopping potential is 1.0V when light of wavelength 6520A˚ is incident on the emitting surface. The stopping potential is 2.9V for light of wavelength 3260A˚. The work function of the metal is

0.9eV

1.9eV

5.8eV