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Q. In an experiment on photoelectric effect, stopping potential is $1.0\, V$ when light of wavelength $6520\,\mathring{A}$ is incident on the emitting surface. The stopping potential is $2.9\, V$ for light of wavelength $3260\, \mathring{A}$. The work function of the metal is

Dual Nature of Radiation and Matter

Solution:

$\frac{h c}{\lambda}=W+e V_{s}$
$\frac{h c}{652 nm }=W+1 eV$
Also, $\frac{h c}{326 nm }=W+2.9 eV$
Equating $h c$ from both the equations
$652(W+1)=326(W+2.9)$
$2(W+1)=W+2.9$
$W=2.9-2$
$W=0.9\, eV$