In an electromagnetic wave in free space the root mean square value of the electric field is Erms = 6V/m-1. The peak value of the magnetic field is :

Question

In an electromagnetic wave in free space the root mean square value of the electric field is Erms = 6V/m-1. The peak value of the magnetic field is : (A) 2.83 × 10-8 T  (B) 0.70× 10-8 T  (C) 4.23 × 10-8 T  (D) 1.41 × 10-8 T

Tardigrade Admin · Accepted Answer

(E rms /B rms ) =c B rms =(E rms /c) =(6/3 × 108) B rms =2 × 10-8 B rms =(B0/√2) B0= √2 × B rms =√2 × 2 × 10-8 =2.83 × 10-8 T

Q. In an electromagnetic wave in free space the root mean square value of the electric field is $E_{r m s} = 6 V / m^{- 1}$ . The peak value of the magnetic field is :

$2.83 \times 1 0^{- 8} T$

$0.70 \times 1 0^{- 8} T$

$4.23 \times 1 0^{- 8} T$

$1.41 \times 1 0^{- 8} T$

$\frac{E _{r m s}}{B _{r m s}} = c$
$B_{r m s} = \frac{E _{r m s}}{c}$
$= \frac{6}{3 \times 1 0 ^{8}}$
$B_{r m s} = 2 \times 1 0^{- 8}$
$B_{r m s} = \frac{B _{0}}{2}$
$B_{0} = 2 \times B_{r m s}$
$= 2 \times 2 \times 1 0^{- 8}$
$= 2.83 \times 1 0^{- 8} T$

Q. In an electromagnetic wave in free space the root mean square value of the electric field is Erms​=6V/m−1. The peak value of the magnetic field is :

2.83×10−8T

0.70×10−8T

4.23×10−8T

1.41×10−8T