In an electromagnetic wave, E=1.2 sin (2 × 106 t-k x) N / C If the value of intensity of magnetic field is (1/x π)( A m -1), then find x.

Question

In an electromagnetic wave, E=1.2 sin (2 × 106 t-k x) N / C If the value of intensity of magnetic field is (1/x π)( A m -1), then find x. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

c B0=E0 B0=(E0/c)=(1.2/3 × 108)=μ0 H ⇒ H0=(B0/μ0)=(1.2/3 × 108 × 4 π × 10-7) H0=(10-2/π) A m -1

Q. In an electromagnetic wave,
$E = 1.2 sin (2 \times 1 0^{6} t - k x) N / C$
If the value of intensity of magnetic field is $\frac{1}{x π} (A m^{- 1})$ , then find $x$ .

$c B_{0} = E_{0}$
$B_{0} = \frac{E _{0}}{c} = \frac{1.2}{3 \times 1 0 ^{8}} = μ_{0} H$
$\Rightarrow H_{0} = \frac{B _{0}}{μ _{0}} = \frac{1.2}{3 \times 1 0 ^{8} \times 4 π \times 1 0 ^{- 7}}$
$H_{0} = \frac{1 0 ^{- 2}}{π} A m^{- 1}$

Q. In an electromagnetic wave, E=1.2sin(2×106t−kx)N/C If the value of intensity of magnetic field is xπ1​(Am−1), then find x.

cB0​=E0​ B0​=cE0​​=3×1081.2​=μ0​H ⇒H0​=μ0​B0​​=3×108×4π×10−71.2​ H0​=π10−2​Am−1

Q. In an electromagnetic wave,
$E = 1.2 sin (2 \times 1 0^{6} t - k x) N / C$
If the value of intensity of magnetic field is $\frac{1}{x π} (A m^{- 1})$ , then find $x$ .

$c B_{0} = E_{0}$
$B_{0} = \frac{E _{0}}{c} = \frac{1.2}{3 \times 1 0 ^{8}} = μ_{0} H$
$\Rightarrow H_{0} = \frac{B _{0}}{μ _{0}} = \frac{1.2}{3 \times 1 0 ^{8} \times 4 π \times 1 0 ^{- 7}}$
$H_{0} = \frac{1 0 ^{- 2}}{π} A m^{- 1}$