In an ac circuit an alternating voltage e=200 √2 sin 100 t volts is connected to a capacitor of capacity 10 μ F. The r.m.s. value of the current in the circuit is :-

Question

In an ac circuit an alternating voltage e=200 √2 sin 100 t volts is connected to a capacitor of capacity 10 μ F. The r.m.s. value of the current in the circuit is :- (A) 10 mA (B) 100 mA (C) 200 mA (D) 20 mA

Tardigrade Admin · Accepted Answer

I rms =( V rms / X C )= V rms ω c ⇒ I rms =200 × 100 × 10 × 10-6 =200 mA

Q. In an ac circuit an alternating voltage $e = 2002 sin 100 t$ volts is connected to $a$ capacitor of capacity $10 μ F$ . The r.m.s. value of the current in the circuit is :-

10 mA

100 mA

200 mA

20 mA

$I_{r m s} = \frac{V _{r m s}}{X _{C}} = V_{r m s} ω c$
$\Rightarrow I_{r m s} = 200 \times 100 \times 10 \times 1 0^{- 6}$
$= 200 m A$

Q. In an ac circuit an alternating voltage e=2002​sin100t volts is connected to a capacitor of capacity 10μF. The r.m.s. value of the current in the circuit is :-