In above circuit if current through 10 Ω resistor is 2.5 A, value of R is .

Question

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/acc01b4b720b09732ba4b5883d3ffebc-.png" /> In above circuit if current through 10 Ω resistor is 2.5 A, value of R is . (A) 50 Ω (B) 40 Ω (C) 8 Ω (D) 10 Ω

Tardigrade Admin · Accepted Answer

i1=2.5 A so i=i1+i2 So voltage across 10 Ω=i × R=25 Voltage across 40 Ω=10 × 2 .=25 V R=(25/i1+i2) i2=(25/40) A ∴ R=8 Ω

Q.
In above circuit if current through $10 Ω$ resistor is $2.5 A$ , value of $R$ is _______.

$50 Ω$

$40 Ω$

$8 Ω$

$10 Ω$

$i_{1} = 2.5 A$
so $i = i_{1} + i_{2}$
So voltage across $10 Ω = i \times R = 25$
Voltage across $40 Ω = 10 \times 2. = 25 V$
$R = \frac{25}{i _{1} + i _{2}}$
$i_{2} = \frac{25}{40} A$
$∴ R = 8 Ω$

Q. In above circuit if current through 10Ω resistor is 2.5A, value of R is _______.

50Ω

40Ω

8Ω

10Ω