In ABC ABC packing if the number of atoms in the unit cell is n then the number of tetrahedral voids in the unit cell is equal to

Question

In ABC ABC packing if the number of atoms in the unit cell is n then the number of tetrahedral voids in the unit cell is equal to (A) n (B) n/2 (C) n/4 (D) 2n

Tardigrade Admin · Accepted Answer

Number of tetrahedral voids per atom in a unit cell is 2. Hence the total number of tetrahedral voids = 2n.

Q. In $A BC$ $A BC$ packing if the number of atoms in the unit cell is $n$ then the number of tetrahedral voids in the unit cell is equal to

$n$

$n /2$

$n /4$

$2 n$

Number of tetrahedral voids per atom in a unit cell is $2$ . Hence the total number of tetrahedral voids $= 2 n$ .

Q. In ABC ABC packing if the number of atoms in the unit cell is n then the number of tetrahedral voids in the unit cell is equal to

n

n/2

n/4

2n

Number of tetrahedral voids per atom in a unit cell is 2. Hence the total number of tetrahedral voids =2n.

Q. In $A BC$ $A BC$ packing if the number of atoms in the unit cell is $n$ then the number of tetrahedral voids in the unit cell is equal to

$n$

$n /2$

$n /4$

$2 n$

Number of tetrahedral voids per atom in a unit cell is $2$ . Hence the total number of tetrahedral voids $= 2 n$ .