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Chemistry
In ABC ABC packing if the number of atoms in the unit cell is n then the number of tetrahedral voids in the unit cell is equal to
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Q. In $ABC$ $ABC$ packing if the number of atoms in the unit cell is $n$ then the number of tetrahedral voids in the unit cell is equal to
The Solid State
A
$n$
12%
B
$n/2$
25%
C
$n/4$
38%
D
$2n$
25%
Solution:
Number of tetrahedral voids per atom in a unit cell is $2$. Hence the total number of tetrahedral voids $= 2n$.